Answer in Statistics and Probability for Syerra #248830
October 24th, 2022
how many ways can 4 baseball players and 4 basketball players be selected from 15 baseball players and 9 basketball players?
“C^{15}_4 times C^{9}_4 = frac{15!}{4!(15-4)!} times frac{9!}{4!(9-4)!} \nn= frac{12 times 13 times 14 times 15 }{2 times 3 times 4} times frac{6 times 7 times 8 times 9}{2 times 3 times 4} \nn= 1365 times 126 = 171990”