Answer in Statistics and Probability for Shivam Nishad #88353
January 24th, 2023
Solution. Suppose event A is a second ball is white; B1 is the first ball is white; B2 is the first ball is red. Using the Law of Total Probability for our case get
“P(A)=P(A/B_1)P(B_1)+P(A/B_2)P(B_2)”
According to the condition of the problem
“P(B_1)=frac {6} {10}”
“P(B_2)=frac {4} {10}”
“P(A/B_1)=frac {5} {9}”“P(A/B_2)=frac {6} {9}”
As a result, we get
“P(A)=frac {6} {10} *frac {5} {9}+frac {4} {10} *frac {6} {9}=frac{30} {90}+frac{24} {90}=frac{54} {90}=0.6”
Answer. 0.6
