Answer in Statistics and Probability for Asubonteng Isaac Adjei #119409

This problem is of Poisson Distribution.

We are given, error for one minute is 0.0001

So error for 20 minutes will be = 20*0.0001 = 0.002

Hence “lambda” = 0.002

Since Poisson Distribution is given by

“P(X = x) = frac{ (e^{- lambda })(lambda^{x})}{x !}”

Here, x = 0 as there is no error.

Putting values in the equation,

“P(X = x) = frac{ (e^{- 0.002 })(0.002^{0})}{0 !}”

Solving this we will get

P(x = x) = 0.998001998667 = 0.998