Answer in Organic Chemistry for emily #119303
April 21st, 2023
- Amount of energy absorbed by water:
“q=cmDelta T = 4.186 frac{J}{gtimes ^circ C} times 250.0 g times (36.0 ^circ C-20.5 ^circ C)= 16220.75 J”
2.Moles of solute:
“2.35 g Mg(OH)_2 times (frac{1 mole Mg(OH)_2}{58.32 g Mg(OH)_2})= 0.0403 mol”
3.As the temperature is increased then the reaction is exothermic, then:
“Delta H_{soln}= frac{-q}{n}”
“Delta H _{soln} = frac{-16220.75 J}{0.0403 mol}=-402500 frac{J}{mol}=- 403 frac{kJ}{mol}”