Answer in Optics for Nicholas Legault #87951
February 20th, 2023
The width of the interferential band is given by formula
“u0394=frac { lambda L}{d} (1)”
where d=205×10-6 m, L=3 m, λ=638.2×10-9 m
Using (1) we got: Δ=9.43×10-3 m
In this case, the distance from the first to the seventh nodal line is equal to
“9.43u00d710^ {-3 } mtimes6 =56.58u00d710^{-3} m”
Calculated value (56.58 mm) is agreed with experimental value (56.9 mm).
Answer:
The teacher gave accurate value for the separation of the pinholes.
