Answer in Optics for Kundan #87330
February 20th, 2023
The condition for interference is
“{2}{t}={m}{lambda} (1)”
where t is the thickness of the air wedge at a distance x from the point of contact of the glass plates.
θ is the angle between the plates in radians (this angle is small, so tan θ = θ in radians). In this case, we got
“theta=frac{t}{x} (2)”
So
“2{theta}{x}={m}{lambda} (3)”
We got
“frac{m}{x}=frac{2theta}{lambda} (4)”
20” is equal to 9.59×10-5 radians
Using (4) we get 3.29 fringes/cm
Answer:
3.29 fringes/cm