# Answer in Mechanics | Relativity for Sammy W-S #125868

The problem’s solution is based on 2,3 – Newton laws and the connection equation:

“m_1vec a_1 = m_1vec g+vec T_1 + vec N_2”

“m_2vec a_2 = m_2vec g+vec N_1 + vec P_h” h – human

“m_hvec a_h = m_hvec g+vec T_2”

“vec N_2+vec N_1 = 0”

“vec T_2+vec P_h = 0”

“x_1-x_0 + y_0-y_1 = const”

We can take the second derivative from the last eqution and have had: “a_1 = a_2 = a_h = a”

Then in the projection on XY plane, vector equations become next scalar equations:

“m_1a = -N_2” (1)

“m_2a = m_2g+P_h-N_1” (2)

“m_ha_h = m_hg-T_2” (3)

“N_2-N_1=0” (4)

“T_2-P_h=0” (5)

“a_1 = a_2 = a_h = a” (6)

This system of equations we can solve with respect to a:

“a = frac{m_1+m_h}{m_2+m_h-m_1}g”

And from (3),(5) get “P_h”

“P_h = frac{m_1m_h}{m_2+m_h-m_1}g”

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