Answer in Mechanics | Relativity for Leticia S #138937
March 12th, 2023
Solution
Given Forces can be shown below
“F_1=50N\F_2=50N\”
Firstly we have to find components in
“F_{3_x}=F_3cos30^u00b0=60.62N\F_{3_y}=F_3sin30^u00b0=35N”
Now in resultant forces are found in -x and +y axis as shown below

Finally resultant force of all three forces is given by
“F_R=sqrt{15^2+(10.62) ^2}” =337.8N