Answer in Mechanics | Relativity for Holden Giles Cabrito #140531
August 13th, 2023
a) The resultant displacement is AD vector. AD = AB + BC + CD = AC + CD
“|AC|^2 = |AB|^2 + |BC|^2 – 2 |AB| |BC| cos 45 ^circ = 6.3^2 +12^2 – 2 cdot 6.3 cdot 12 cdot cos 45 ^circ = 76.77”
“|AC| = 8.76” km.
“|AD|^2 = |AC|^2 + |CD|^2 – 2 |AC| |CD| cos (90^circ + 30^circ) = 8.76^2 +4.7^2 – 2 cdot 8.76 cdot 4.7 cdot cos (120^circ) = 140”
“|AD| = 11.83” km.
b) Total distance travelled is 6.3 km + 12 km + 4.7 km = 23 km.
Answer: a) 11.83 km, b) 23km.