Answer in Mechanics | Relativity for Holden Giles Cabrito #138633

According to the Newton’s first law: “Sigmavec{F}=0” and

“Sigmavec{F_{x}}=0” , where “vec{F_{x}}”– projection of any force to the x axis.

1) When the rope is parallel to the incline:

“|vec F|= |vec G_{x}|=|vec G|cdot sin(30u00b0)=3200cdotfrac{1}{2}=1600” lb.

2) When the rope makes 60 degrees with the horizontal:

“|vec F_{x}|= |vec G_{x}|=|vec G|cdot sin(30u00b0)=3200cdotfrac{1}{2}=1600” lb;

“|vec F|=frac{ |vec F_{x}|}{cos(30u00b0)}=frac{1600}{sqrt3/2}approx1847.5” lb.

Answer: 1)when the rope is parallel to the incline the tension on the rope is 1600 lb;

2)when the rope makes 60 degrees with the horizontal the tension on the rope is about 1847.5 lb.