Answer in Mechanics | Relativity for Carl Nicole Legario #108465
March 12th, 2023
Given that,
A direct compressive force of 240,000 N is applied to a solid piece of material of rectangular cross-section, 8 cm by 5 cm.
Therefore the total cross sectional area = “8cmtimes5cm=40cm^2”
Pressure acting on the solid piece of material by the compressive force is given by,
“P=frac{F}{A}=frac{240000}{40 times 10^{-4}}”
“=6times10^{7}Nm^{-2}”