Answer in Mechanics | Relativity for Aobakwe #145241
March 12th, 2023
M = 1916 kg
R = 1.2 m
a. The rotational inertia
“I = frac{2}{5}mR^2”
“I = frac{2}{5} times 1916 times 1.2^2”
I = 1103.6 kgm2
b. “fR = Ifrac{gsinu03b8}{R}”
“f = frac{I times g times sin(29u00ba)}{R^2}”
“f = frac{1103.6 times 9.8 times 0.4848}{1.2^2} = 3641.14 ;N”
c. Speed
“v = w times R”
The angular velocity
“w = frac{2u03c0}{T}”
“T = frac{5.5}{8} = 0.687 ;s”
“w = frac{2u03c0}{0.687} = 9.14 ;rad/s”
“v = 9.14 times 1.2 = 7.61 ;m/s”
d. Distance
“S = v times 5.5 ;s = 7.61 times 5.5 = 1.38 ; m”
