Answer in Mechanical Engineering for SID #211713
February 20th, 2023
An ice making machine operates on the ideal vapor compression cycle, using R-134a. The refrigerant
enters the compressor as saturated vapor at 140kPa and leaves the condenser as saturated liquid at
700kPa. Water enters the ice machine at 13 0 C and leaves as ice -4 0 C. For an ice production rate of 9kg/h,
determine the power input to the ice machine.
From the data given
“h_1 = 238.97 kJ/kg; h_2=267.51kJ/kg; h_3=h_4=77.67 kJ/kg”
Cooling load
“dot{Q_L}=dot{m_{ice}} triangle{h_{ice}} = frac{9}{3600}*455.896 =1.13974 kJ”
Refrigerant mass
“dot{m_R}=frac{dot{Q_L}}{h_1-h_4}=frac{1.13974}{238.97-77.67}=0.007066 kg/s”
The power input
“W_{in}=dot{m_R}(h_2-h_1) = 0.007066(267.51-238.97)=0.20166 kJ/s = 0.27043 hp”