Answer in General Chemistry for Tuti #152806
March 17th, 2023
Calculate the time required to deposit 0.37g of Silver from a silver Nitrate solution using a current of 2.5A ( Charge of Ag in is AgNO 3 is +1)
If Farade constant = 96485 Cmol-1
Atomic mass of Ag = 107.5 gmol-1
- Deposition occurs as,
Ag+(aq) + e ——> Ag(s) —- (1)
- No of Ag moles deposited ( nAg ) = “dfrac{0.37g}{107.5gmol^{-1}}”
= “3.44times10^{-3} mol”
- As per the equation (1),
“n_e = n_{Ag}\”
- Using,
“Q =It,\3.44times10^{-3}mol;times ;96485; Cmol^{-1};=;2.5A;times;t\nt;=;bf132.76s”