Answer in General Chemistry for taiya #149846
March 18th, 2023
“N2 + 3H2 to 2NH3\n u2206H = – 92.6 kJ /mol”
From the reaction above, when 2 moles of NH3 is produced, 92.6kJ is evolved
This means that 34g of NH3 = 92.6kJ
30.4mg = xkJ
x = (30.4/1000g × 92.6)/34g = 0.0828kJ = 82.8J.
This means 82.8J is evolved in the reaction.
Using, H = mc∆T
H = 82.8J
m = 350g
∆T = 4
c = H/m∆T = 82.8/350×4 = 0.0591 J/g.°C