Answer in General Chemistry for taiya #149844
March 18th, 2023
First calculate the amount of heat needed to increase the temperature of a 333-gram block of iron from 22⁰C to 1300⁰C:
“Q = cmDelta T = 0.49 * 333 * (1300-22) = 208531 (J) = 208.5 (kJ)”
If 3 moles of NO2 are needed to produce 138 kJ of heat, then calculate the amount of NO2 needed to produce 208.5 kJ of heat:
“nu = 208.5*3/138 = 4.53 (mol)”
Answer: 4.53 moles of NO2 are needed to increase the temperature of a 333-gram block of iron from 22⁰C to 1300⁰C.