Answer in General Chemistry for Ryne Salas #155689

F 100.0 g of iron three hydroxide is mixed with 80.0 g of sulfuric acid acid what will be the limiting reactant

The balanced equation for the reaction;

2Fe(OH)₃ + 3H₂SO₄ “to” Fe(SO4)₃ + 6H₂O

Moles of Iron(III)hydroxide available

1mole “implies” 107g

? “implies” 100g

“=dfrac{1molx100g}{107g}”

= 0.9346mol

Moles of H2SO4 required to completely react with 100g of Iron (III) hydroxide;

Mole ratio of Fe(OH)₃ : H₂SO₄ = 2:3

Moles of H2SO4 “=dfrac{3}{2} x0.9346 = 1.4019mol”

Moles of H2SO4 available “= dfrac{mass}{RFM} = dfrac{80g}{98g/mol} = 0.8163mol”

Therefore, the moles of H₂SO₄ available are less than required, hence H₂SO₄ is the limiting reagent