Answer in General Chemistry for O.Weerasinghe #152377
March 17th, 2023
CxHy + O2 → CO2 + H2O
CxHy + (x+y/4)O2 → xCO2 + (y/2)H2O
V(CxHy) = 18 cm3
V(H2O) = 162 cm3
V(CO2) = 126 cm3
“frac{n(CO_2)}{n(C_xH_y )} = frac{x}{1} = frac{126}{18} \nnx = 7 \nnfrac{n(CO_2)}{n(H_2O)} = frac{x}{frac{y}{2}} \nnfrac{2x}{y} = frac{126}{162} \nn frac{14}{y} = frac{126}{162} \nny = 18”
Answer: C7H18