Answer in General Chemistry for mya #152996

the volume of the column is 39ml calculated using the given data

the mobile phase retention time can be calculated using equation

t_M = “frac{V_Cu03b5}{Q}” “implies” “frac{39(0.25)}{10}” = 0.975 min

the retention times can be calculated using equation

t_R = t_M {1+ ( “frac{1-u03b5}{u03b5}” ) K}

t_R,alb = 0.975 { 1 + (“frac{1-0.25}{0.25}” ) 0.1 } = 1.25 min

t_R,IgG = 0.975 { 1 + (“frac{1-0.25}{0.25}”) 1 } = 3.9 min

the number of theoretical plates in the column can be calculated from albumin retention time data using equation

N = 16(“frac{t_g}{w}” )² “implies” 16 (“frac{1.27}{0.52}”)² = 95

the peak width of IgG can be calculated using equation

W_IgG = “frac{t_{R.IgG}}{sqrtfrac{N}{16}}” “implies” “frac{3.9}{sqrtfrac{95}{16}}” = 1.6 min

the resolution of separation can be calculated using equation

R = “frac{t_{R2}-t_{g1}}{0.5(w_1+w_2)}” “implies” “frac{3.9-1.27}{0.5(1.6+0.52)}” = 2.58

the selectivity can be calculated using equation

α = “frac{K_2}{K_1}” = “frac{t_{R2}-t_M}{t_{R1}-t_M}” “implies” “frac{1}{0.1}” = 10

the height of the theoritical plate can be calculated using equation

H = “frac{l}{N}” = “frac{50}{95}” = 0.526 cm