Answer in General Chemistry for Michael Gordon #152383
March 17th, 2023
“2NO_{(g)} +O_{2(g)} to 2NO_{2(g)}”
With 2moles of NO and 1 mole of O2 in 1litre flask.
2.5 X 10-3[NO] + 1.25X 10-3[O2] -> 2.51 X 10-3[NO2] at equilibrium.
Hence equilibrium constant,
Kc = “dfrac{[NO_2]^2}{[NO]^2[O2]}” = “dfrac{[2.51u00d710^{-3}]^2}{ [2.51 u00d710^{-3}]^2 u00d7[ 1.25 u00d7 10^{-3}]}” = 8×10²
Since Kc >> 1 reaction is almost complete and equilibrium exists at the product.