Answer in General Chemistry for Megan Wakley #149860

Given that the mass of tea in the cup = 175 g

Final temperature = 27°С

Initial temperature = 85°С

Let us assume the specific heat of tea is equal to that of water = 4.184 J/g°C

Temperature change = T_final – T_initial = (27 – 85) = – 58°C 

-Heat given out by tea = heat absorbed by the surroundings

Heat released into the surroundings =-mC(T_final – T_initial) = -175 g × 4.184 J/g°C x (-55°C) = 40 271 J = 40.271 kJ