Answer in General Chemistry for mari #152234
March 17th, 2023
Cu2Mg + 2HCl → MgCl2 + H2 + 2Cu
At STP 1 mole of gas occupies 22.4 L.
Proportion 1:
1 mol – 22.4 L
x – 1.12 L
“x = frac{1 times 1.12}{22.4} = 0.05 ;mol”
n(Cu2Mg) = n(H2) = 0.05 mol
MM(Cu2Mg) = 151.39 g/mol
m(Cu2Mg) “= 0.05 times 151.39 = 7.57 ;g”
Proportion 2:
7.57 g – 100 %
3 g – y
“y = frac{3 times 100}{7.57} = 39.63” %
Answer: 39.63 %