Answer in General Chemistry for Edikandinho #280202
April 21st, 2023
Cal. PH and POH for each of the following solutions at 25°c.
i) 1.0×10^-3 OH-
I) 1.0m H+
pH + pOH = 14
pH = – lg [H+]
pOH = – lg [OH–]
1) pOH = – lg [1.0×10-3] = 3
pH = 14 – 3 = 11
2) pH = – lg [1.0] = 0