Answer in General Chemistry for Dave #149769
March 18th, 2023
2Na3N = 6Na + N2
PV = nRT
n = PV/RT
= 1 ×60 / 0.082 × 298
= 2.46moles
2. Mole of Na3N = 2.46/2 = 1.23 moles
3. Mass of Na3N = 1.23 × (83) = 102.09g
2Na3N = 6Na + N2
PV = nRT
n = PV/RT
= 1 ×60 / 0.082 × 298
= 2.46moles
2. Mole of Na3N = 2.46/2 = 1.23 moles
3. Mass of Na3N = 1.23 × (83) = 102.09g