Answer in General Chemistry for Danyal #153471
March 17th, 2023
Calculate the percentage yield of ethanol when 100 g of glucose is fermented to make 20 g of ethanol.
the normal reaction of glucose fermentation to ethanol is
“C_6H_{12}O_{6(aq)}to 2C_2H_5OH_{(aq)} +2CO_{2(g)}”
from the reaction above,
1 mole of glucose ferments to form 2 moles of ethanol
This means that, 180g of glucose ferments to form 92g (2×46) of ethanol
100g of glucose should therefore ferment to form 51.1g (“dfrac{100u00d792}{180}”) of ethanol
from, “% yield = dfrac{textsf{Actual Yield}}{textsf{Theoretical Yield}} u00d7 100%”
“%yield = dfrac{20g}{51.1g} u00d7 100% = 39.14”%
This means that the percentage yield of ethanol when 100 g of glucose is fermented is 39.14%