Answer in Electric Circuits for Stephen #159502
October 16th, 2022
Suppose the “vertical attenuator” of an A.C signal is set to 0.5v/Div and the probe factor is 10,if signal occupies 5 divisions vertically.What is the peak to peak voltages and the rms equivalent.
Peak to peak voltage equals
“V_{p-p}=K_acdot K_pcdot Y=0.5cdot 10cdot 5= 25space V,”
where “K_a” – the vertical attenuator factor;
“K_p” – the probe factor;
Y – number of divisions, occupied by the sygnal.
RMS voltage equals
“V_{rms}=frac{V_{p-p}}{sqrt{2}}=frac{25}{sqrt{2}}approx17.7space V.”
Answer: peak to peak voltage equals 25 V, RMS voltage equals 17.7 V.
