Answer in Chemical Engineering for pavani #231373
March 11th, 2023
5) Find the particular integral of ∂²z/∂x²-3 ∂²z/∂x∂y+∂²z/∂y²= 2x sin y.
Given equation can be written as 2 2 = 1 …(1) Integrating (1) w. r. t., , we get = 2 2 + ∅1(y) …(2) where ∅1(y) is an arbitrary function of y Integrating (2) w. r. t., x, z = 3 6 + x ∅1(y) + ∅2(y)
Multiplying (1) by we get + = 9 2 3 ⇒ = 9 2 3 ⇒ = 9 3 3 3 + ⇒ = 3 3 3 +
