Answer in Chemical Engineering for pavani #231366
March 11th, 2023
2) Find the Laplace transform of the periodic function f(t)=t ,0≤t≤2 and f(t+2)=f(t)?
Here f(t)=t, your limits will not varay from +inf to -inf but from 0 to 2.
For periodic function however it takes a different form which nothing but a highly specialized one by using certain constraints.
The answer will be like :
“frac{1}{(1-e^-2s)*[-((2*e^-2s)/s)-((e^-2s)/(s^2))+1/s^2]}”
