Answer in Algebra for Kay #109823

(a) Let’s calculate t₀ = time when debris reach the ground.

“h=-16t^2+975\When;debris;reach;the;ground,;h=0.\0=-16t_0^2+975\t_0^2=frac{975}{16}Rightarrow t_0=sqrt{frac{975}{16}}Rightarrow t_0approx7.806s\”

(b) Let’s calculate t₁ = time when people on the street hear the crash.

So, answer will be t₀-t₁ = time people have to get out of the way after hearing before debris fall.

“t_0approx7.806sec\t_1=frac{975ft}{1100ft/s}approx0.886s\t_0-t_1=7.806s-0.886s;=;6.92s”

Answer: (a) 7.806s (b) 6.92s